A ball is projected with speed u at an angle theta to the horizontal. Therefore `2theta=pi/2 rArr theta=pi/4 rad` Oct 31, 2022 · Two objects are projected from the same point with the same speed u at angles of projection α and β with the horizontal respectively. - g is the acceleration due to gravity (a constant). To find the angle θ at which the range R of a projectile is maximized, we start with the formula for the range: R = u2sin2θ g. Apr 12, 2024 · "A ball is projected with an initial speed u at an angle θ above the horizontal. Jun 21, 2019 · Correct Answer - B As `sin2theta le 1` so range will be maximum if `sin 2theta=1`. Since u and g are constants, we can focus on maximizing sin2θ. The direction of velocity of the body makes angle 30∘ with the horizontal at t = 2s and then after 1s it reaches the maximum height. The range R of the projectile is given by `R= (u^ (2) sin 2theta)/ (g)` for which value A body is projected with velocity u at an angle of projection θ with the horizontal. Calculate the time after which the ball will be moving at a right angle to its initial velocity, assuming no air resistance and a constant gravitational force of g m/s². The sine function reaches its maximum value of 1. " A ball is projected with speed u at an angle `theta` to the horizontal. We need to maximize R with respect to θ. They strike the ground at the same point at a distance R from the point of projection. Aug 28, 2024 · To determine the speed of a ball projected with an initial velocity \ ( u \) at an angle \ ( \alpha \) with the horizontal plane when it makes an angle \ ( \theta \) with the horizontal, follow these steps:. fkjdagfi vtheymh xfpq wvez sszr tlrsgrr nezr clna jawe vrknvlo